Web студия "GrandView"

Примечания

Внимание

Если вы собираетесь передавать функции данные, отправленные пользователем, вы должны использовать функции escapeshellarg() или escapeshellcmd() для того, чтобы обезопасить исполнение команд.

Замечание: Если вы собираетесь использовать эту функцию в программе, работающей в качестве демона, убедитесь, что стандартный вывод функции направлен в файл или другой поток, в противном случае PHP зависнет вплоть до конца выполнения программы.

Замечание: В случае работы в безопасном режиме, вы можете запускать что-либо только в пределах safe_mode_exec_dir. В настоящее время, использование .. в пути запрещено

Внимание

В случае работы в безопасном режиме, все слова, следующие за начальной командой, рассматриваются как единый аргумент. То есть echo y | echo x будет работать как echo "y | echo x".

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system

toby at globaloptima dot co dot uk
20-Sep-2007 02:16


Regarding Billybob's comment about multi-line system commands like this:



$commandeDB1 = system ("cd \

                       cd mysql

                       cd bin

                       mysql -uroot -pedfdiver -P3307

                       use diver_1

                          insert into cdn_flv_8(flv_file,cdn_dn_or_ip,video_path,flv_groups

    values('$fichier','130.98.61.32','/diver_edf/video_1/','0');");



First things first, this kind of mysql interaction should be taken care of with the in-built mysql or mysqli PHP libraries, it make much more sense when you see it, loads and loads of tutorials online about this exact subject:



http://php.net/mysql



See how you can do exactly the same thing without using the system command:



$link = mysql_connect('localhost', 'root', 'edfdiver');

mysql_select_db('diver_1')

mysql_query("your insert sql here");

mysql_close($link);



Also you no longer rely on MySQL being located in a certain folder, your script is cross-platform, easier to understand and generally far more robust.



Regarding multi-line statements using the system function, the only way I've done this in the past is to separate each command with a semi-colon which in some cases is useful but most of the time seems to be a really bad way of doing things (this is using Linux, BASH Shell, I expect Windows has similar mechanism).



Note that you don't seem to be able to set shell variables either, again using BASH:



x=10;echo $x



This works on the command line, running via system prints an empty line, may be possible but I've not managed it yet.



Also in your example, commands 1,2,3 and 4 are for the Operating System whilst commands 5 and 6 are for MySQL, try putting a semi-colon between each of your commands to see what happens.



My advice, if you are new-ish to PHP, is to try and avoid the system/exec/passthru functions and stick with in-built PHP libraries where-ever possible, most things you want to do can be handled by these libraries.



And additions to this are welcome, I'm no expert, just a few things I've noticed.



Toby

Billybob
13-Sep-2007 07:39


Hi



I'm a newbie in php, and I was wondering if it's possible to use multiple line with "system". Here is an example:



$commandeDB1 = system ("cd \

                       cd mysql

                       cd bin

                       mysql -uroot -pedfdiver -P3307

                       use diver_1

                          insert into cdn_flv_8(flv_file,cdn_dn_or_ip,video_path,flv_groups

    values('$fichier','130.98.61.32','/diver_edf/video_1/','0');");



Thanks

willytk at gmail dot com
10-Sep-2007 05:39


If you're having problems with getting imagemagick/convert to work with ghostscript because the gs executable isn't in the apache PATH, do the following:



To create a thumb of the first pdf page:



<?php

$command= 'export PATH=$PATH:/sw/bin; convert "files/example.pdf[0]" -thumbnail 150x150 "files/thumbs/example.png"';



$lastline = system($command,$return);

?>



Thanks entropy.ch and phpaladin!



Regards,



Willy T. Koch

Oslo, Norway

timgolding_10 at hotmail dot com
20-Jul-2007 07:19


An example of using the system to call the file command on a linux server. This script detects whether a user posted file is a jpeg, gif or png



<?PHP



$accepted_types=array("JPEG" , "GIF", "PNG"); 



    // The temporary filename of the file in which the uploaded file was stored on the server. 

if(!empty($_FILES["uploadedfile"]))

  {

    $uploaddir = $_SERVER['DOCUMENT_ROOT']."/images/";

    $uploaddir.=basename( $_FILES['uploadedfile']['name']);

   

 //verfiy file using linux FILE command 

 $last_line = system('file '.escapeshellarg($_FILES['uploadedfile']['tmp_name']), $retval);



 //get the file extension returned through magic database

 $splitvals=explode(' image data' ,  $last_line);

 $vals=explode(':', $splitvals[0]);

 $vals[1]=str_replace(' ','', $vals[1]); 



 if (in_array($vals[1], $accepted_types))

 {

    echo $vals[1].' was accepted <br />';

        if(!file_exists($uploaddir)){

            //Copy the file to some permanent location

            if(move_uploaded_file($_FILES["uploadedfile"]["tmp_name"], $uploaddir))

             {

              echo $uploaddir." was uploaded! <br />";

             }

            else

             {

              echo "There was a problem when uploding the new file, please contact admin about this.";

             }

        }

        else echo 'This file already exists in DB please rename file before uploading';

}

}else echo $_FILES['uploadedfile']['error'].'<br />';

?>

aaron at visual-code dot com
01-Jul-2007 04:41


Regarding the running of processes in the background.  i found that after a few different attempts that this worked fine and allowed the main script to continue unhindered.



Hope that this might help someone.



$arg1 = "arg1";

$arg2 = "arg2";

$page = "/path/tothe/script/scriptToRun.php";

$args = "--arg1='".urlencode($arg2)."' --arg2 ='".urlencode($arg2)."'";

$command = "(php -c /usr/local/lib/php.ini ".$page." ".$args." &) > /dev/null";

system($command);

eis
20-Jun-2007 02:11


It should be noted, too, that "unable to fork" error in Windows also occurs if you try to send a command that's too long for cmd.exe to process.

peter at randomnity dot com
28-Mar-2007 10:09


Just a note to dan at thecsl dot org



0 and FALSE are _NOT_ the same.

You can check for false like so:



<?php

if($return_val === FALSE) {

   // ....

} else if ($return_val == 0) {

   // ...

}

// Continue...

?>

jordan314 at mailinator dot com
20-Mar-2007 01:44


z1a7n8g, your system logging to file function was really useful, but had two errors:

$line=fgets($fPtr,filesize("yourfile.php");

that line needs a second closing ')'

and:

while ($line)

returns true until your script runs out of memory. Those two lines can be combined:

while($line=fgets($fPtr,filesize("yourfile.php")));

norman_ss at hotmail dot com
08-Mar-2007 03:43


thanks to tr4nc3,



I'm trying to, from the explorer, run an access's macro and this example give me the solution:



You can execute a .bat file with the especifications that give us tr4nc3.

After, in this .bat file, you can execute msacces.exe and pass /x parameter with the name of the macro. like this:



"c:\windows\system32\cmd.exe /c <path or the msaccess.exe>" <path of the .mdb file> /x <name of the macro>"



At the end of the .bat file you have to put "exit" and the thread will end.



Thanks to tr4nc3!

dotmg at wikk

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