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similar_text

(PHP 3 >= 3.0.7, PHP 4, PHP 5)

similar_text --  Вычисляет степень похожести двух строк

Описание

int similar_text ( string first, string second [, float percent] )

Вычисляет степень похожести двух строк по алгоритму, описанному Oliver [1993]. Эта реализация алгоритма не использует стэка, использованного в оригинале, вместо этого применяются рекурсивные вызовы, что в некоторых случаях может ускорить процесс. Сложность алгоритма составляет O(N**3), где N - длина более длинной из двух строк.

При передаче по ссылке третьего аргумента, ему присваивается степень похожести двух строк в процентах. Возвращается количество совпадающих символов в двух строках.



soundex> <sha1
Last updated: Fri, 26 Jan 2007
 
add a note add a note User Contributed Notes
similar_text
romain dot boyer at gmail dot com
08-Aug-2007 05:59
Like levenchtein(), You can do :

(strlen($string2) - similar_text($string,$string2))

to see how much characters have been changed.
Paul
18-Jan-2007 08:50
The speed issues for similar_text seem to be only an issue for long sections of text (>20000 chars).

I found a huge performance improvement in my application by just testing if the string to be tested was less than 20000 chars before calling similar_text.

20000+ took 3-5 secs to process, anything else (10000 and below) took a fraction of a second.
Fortunately for me, there was only a handful of instances with >20000 chars which I couldn't get a comparison % for.
dmitry dot polushkin at gmail dot com
07-Mar-2006 08:08
Well... hard to explain, why I have written this function, but maybe it will be usefull.
<?php
// returns the percentage of the string "similarity"
function str_compare($str1, $str2) {
   
$count = 0;
   
   
$str1 = ereg_replace("[^a-z]", ' ', strtolower($str1));
    while(
strstr($str1, '  ')) {
       
$str1 = str_replace('  ', ' ', $str1);
    }
   
$str1 = explode(' ', $str1);
   
   
$str2 = ereg_replace("[^a-z]", ' ', strtolower($str2));
    while(
strstr($str2, '  ')) {
       
$str2 = str_replace('  ', ' ', $str2);
    }
   
$str2 = explode(' ', $str2);
   
    if(
count($str1)<count($str2)) {
       
$tmp = $str1;
       
$str1 = $str2;
       
$str2 = $tmp;
        unset(
$tmp);
    }
   
    for(
$i=0; $i<count($str1); $i++) {
        if(
in_array($str1[$i], $str2)) {
           
$count++;
        }
    }
   
    return
$count/count($str2)*100;
}
?>
brad dot fish at gmail dot com
24-Feb-2006 02:30
The link below to the Oliver document appears to be broken. Here is one that works: http://citeseer.ist.psu.edu/oliver93decision.html
louis #at# mulliemedia.com
06-Jun-2004 05:01
Note that this function will calculate the percentage blindly, without regard to the LENGHT of the string.

This may become important if you try to print similar names to SMALL strings :
e.g.
I want to print out the value if it is 90 percent similar to the other one : the value is HE, the correct value is HEC

The similar_text() function will return approximately 66.7 %, and it will not print it because it is smaller than 90 %, although almost all of the string was matched.
hate at spam dot com dot BR
09-May-2004 09:21
In PHP4+, you don't need to pass the percent variable as reference..
Instead, use this way:
<?
similar_text($string1, $string2, $p);
echo "Percent: $p%";
?>

In PHP5, you'll get a ugly warning message when passing this variable as reference.. But it's configurable in php.ini (allow_call_time_pass_reference = Off)

That's it... Another great function! :)
julius at infoguiden dot no
06-Feb-2003 06:46
If you have reserved names in a database that you don't want others to use, i find this to work pretty good.
I added strtoupper to the variables to validate typing only. Taking case into consideration will decrease similarity.

$query = mysql_query("select * from $table") or die("Query failed");

while ($row = mysql_fetch_array($query)) {
      similar_text(strtoupper($_POST['name']), strtoupper($row['reserved']), $similarity_pst);
      if (number_format($similarity_pst, 0) > 90){
        $too_similar = $row['reserved'];
        print "The name you entered is too similar the reserved name &quot;".$row['reserved']."&quot;";
        break;
       }
    }
georgesk at hotmail dot com
08-Mar-2002 08:14
Well, as mentioned above the speed is O(N^3), i've done a longest common subsequence way that is O(m.n) where m and n are the length of str1 and str2, the result is a percentage and it seems to be exactly the same as similar_text percentage but with better performance... here's the 3 functions i'm using..

function LCS_Length($s1, $s2)
{
  $m = strlen($s1);
  $n = strlen($s2);

  //this table will be used to compute the LCS-Length, only 128 chars per string are considered
  $LCS_Length_Table = array(array(128),array(128));
 
 
  //reset the 2 cols in the table
  for($i=1; $i < $m; $i++) $LCS_Length_Table[$i][0]=0;
  for($j=0; $j < $n; $j++) $LCS_Length_Table[0][$j]=0;

  for ($i=1; $i <= $m; $i++) {
    for ($j=1; $j <= $n; $j++) {
      if ($s1[$i-1]==$s2[$j-1])
        $LCS_Length_Table[$i][$j] = $LCS_Length_Table[$i-1][$j-1] + 1;
      else if ($LCS_Length_Table[$i-1][$j] >= $LCS_Length_Table[$i][$j-1])
        $LCS_Length_Table[$i][$j] = $LCS_Length_Table[$i-1][$j];
      else
        $LCS_Length_Table[$i][$j] = $LCS_Length_Table[$i][$j-1];
    }
  }
  return $LCS_Length_Table[$m][$n];
}

function str_lcsfix($s)
{
  $s = str_replace(" ","",$s);
  $s = ereg_replace("[
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