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mysqli_stmt_affected_rows

(PHP 5)

(no version information, might be only in CVS)

mysqli_stmt->affected_rows -- Returns the total number of rows changed, deleted, or inserted by the last executed statement

Description

Procedural style :

int mysqli_stmt_affected_rows ( mysqli_stmt stmt )

Object oriented style (property):

class mysqli_stmt {

int affected_rows

}

mysqli_stmt_affected_rows() returns the number of rows affected by INSERT, UPDATE, or DELETE query. If the last query was invalid, this function will return -1.

The mysqli_stmt_affected_rows() function only works with queries which update a table. In order to return the number of rows from a SELECT query, use the mysqli_stmt_num_rows() function instead.

Возвращаемые значения

An integer greater than zero indicates the number of rows affected or retrieved. Zero indicates that no records where updated for an UPDATE/DELETE statement, no rows matched the WHERE clause in the query or that no query has yet been executed. -1 indicates that the query has returned an error.

Замечание: If the number of affected rows is greater than maximal PHP int value, the number of affected rows will be returned as a string value.

Примеры

Пример 1. Object oriented style


<?php

$mysqli = new mysqli("localhost", "my_user", "my_password", "world");



/* check connection */

if (mysqli_connect_errno()) {

    printf("Connect failed: %s\n", mysqli_connect_error());

    exit();

}



/* create temp table */

$mysqli->query("CREATE TEMPORARY TABLE myCountry LIKE Country");



$query = "INSERT INTO myCountry SELECT * FROM Country WHERE Code LIKE ?";



/* prepare statement */

if ($stmt = $mysqli->prepare($query)) {



    /* Bind variable for placeholder */

    $code = 'A%';

    $stmt->bind_param("s", $code);

    

    /* execute statement */

    $stmt->execute();



    printf("rows inserted: %d\n", $stmt->affected_rows);



    /* close statement */

    $stmt->close();

}



/* close connection */

$mysqli->close();

?>

Пример 2. Procedural style


<?php

$link = mysqli_connect("localhost", "my_user", "my_password", "world");



/* check connection */

if (mysqli_connect_errno()) {

    printf("Connect failed: %s\n", mysqli_connect_error());

    exit();

}



/* create temp table */

mysqli_query($link, "CREATE TEMPORARY TABLE myCountry LIKE Country");



$query = "INSERT INTO myCountry SELECT * FROM Country WHERE Code LIKE ?";



/* prepare statement */

if ($stmt = mysqli_prepare($link, $query)) {



    /* Bind variable for placeholder */

    $code = 'A%';

    mysqli_stmt_bind_param($stmt, "s", $code);

    

    /* execute statement */

    mysqli_stmt_execute($stmt);



    printf("rows inserted: %d\n", mysqli_stmt_affected_rows($stmt));



    /* close statement */

    mysqli_stmt_close($stmt);

}



/* close connection */

mysqli_close($link);

?>

Результат выполнения данного примера:

rows inserted: 17

add a note User Contributed Notes
mysqli_stmt_affected_rows

Chuck
28-Apr-2007 10:51


I'm not sure whether or not this is the intended behavior, but I noticed through testing that if you were to use transactions and prepared statements together and you added a single record to a database using a prepared statement, but later rolled it back, mysqli_stmt_affected_rows will still return 1.

Carl Olsen
27-Dec-2005 10:34


It appears that an UPDATE prepared statement which contains the same data as that already in the database returns 0 for affected_rows.  I was expecting it to return 1, but it must be comparing the input values with the existing values and determining that no UPDATE has occurred.

add a note

mysqli_stmt_bind_param

mysqli_stat

Last updated: Sat, 27 Jan 2007

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mysqli_stmt_affected_rows

Description

Возвращаемые значения

Смотрите также

Примеры