Web студия "GrandView"

Description

Procedural style:

string mysqli_real_escape_string ( mysqli link, string escapestr )

Object oriented style (both methods are equivalent):

class mysqli {

string escape_string ( string escapestr )

string real_escape_string ( string escapestr )

}

This function is used to create a legal SQL string that you can use in a SQL statement. The string escapestr is encoded to an escaped SQL string, taking into account the current character set of the connection.

Characters encoded are NUL (ASCII 0), \n, \r, \, ', ", and Control-Z.

Возвращаемые значения

Returns an escaped string.

Смотрите также

mysqli_character_set_name().

Примеры

Пример 1. Object oriented style


<?php

$mysqli = new mysqli("localhost", "my_user", "my_password", "world");



/* check connection */

if (mysqli_connect_errno()) {

    printf("Connect failed: %s\n", mysqli_connect_error());

    exit();

}



$mysqli->query("CREATE TEMPORARY TABLE myCity LIKE City");



$city = "'s Hertogenbosch";



/* this query will fail, cause we didn't escape $city */

if (!$mysqli->query("INSERT into myCity (Name) VALUES ('$city')")) {

    printf("Error: %s\n", $mysqli->sqlstate);

}



$city = $mysqli->real_escape_string($city);



/* this query with escaped $city will work */

if ($mysqli->query("INSERT into myCity (Name) VALUES ('$city')")) {

    printf("%d Row inserted.\n", $mysqli->affected_rows);

} 



$mysqli->close();

?>

Пример 2. Procedural style


<?php

$link = mysqli_connect("localhost", "my_user", "my_password", "world");



/* check connection */

if (mysqli_connect_errno()) {

    printf("Connect failed: %s\n", mysqli_connect_error());

    exit();

}



mysqli_query($link, "CREATE TEMPORARY TABLE myCity LIKE City");



$city = "'s Hertogenbosch";



/* this query will fail, cause we didn't escape $city */

if (!mysqli_query($link, "INSERT into myCity (Name) VALUES ('$city')")) {

    printf("Error: %s\n", mysqli_sqlstate($link));

}



$city = mysqli_real_escape_string($link, $city);



/* this query with escaped $city will work */

if (mysqli_query($link, "INSERT into myCity (Name) VALUES ('$city')")) {

    printf("%d Row inserted.\n", mysqli_affected_rows($link));

} 



mysqli_close($link);

?>

Результат выполнения данного примера:

Error: 42000
1 Row inserted.

add a note User Contributed Notes
mysqli_real_escape_string

tobias_demuth at web dot de
10-Nov-2005 08:54


Note, that if no connection is open, mysqli_real_escape_string() will return an empty string!

arnoud at procurios dot nl
07-Oct-2004 09:05


Note that this function will NOT escape _ (underscore) and % (percent) signs, which have special meanings in LIKE clauses. 



As far as I know there is no function to do this, so you have to escape them yourself by adding a backslash in front of them.

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