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mysqli_insert_id (PHP 5) mysqli_insert_id (no version information, might be only in CVS) mysqli->insert_id -- Returns the auto generated id used in the last query DescriptionProcedural style: int mysqli_insert_id ( mysqli link ) Object oriented style (property): class mysqli { int insert_id }
The mysqli_insert_id() function returns the ID generated
by a query on a table with a column having the AUTO_INCREMENT attribute. If
the last query wasn't an INSERT or UPDATE statement or if the modified table
does not have a column with the AUTO_INCREMENT attribute, this function will
return zero.
Замечание:
Performing an INSERT or UPDATE statement using the LAST_INSERT_ID()
function will also modify the value returned by the
mysqli_insert_id() function.
Возвращаемые значения
The value of the AUTO_INCREMENT field that was updated
by the previous query. Returns zero if there was no previous query on the
connection or if the query did not update an AUTO_INCREMENT
value.
Замечание:
If the number is greater than maximal int value, mysqli_insert_id()
will return a string.
ПримерыПример 1. Object oriented style |
<?php
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$mysqli->query("CREATE TABLE myCity LIKE City");
$query = "INSERT INTO myCity VALUES (NULL, 'Stuttgart', 'DEU', 'Stuttgart', 617000)";
$mysqli->query($query);
printf ("New Record has id %d.\n", $mysqli->insert_id);
$mysqli->query("DROP TABLE myCity");
$mysqli->close();
?>
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Пример 2. Procedural style |
<?php
$link = mysqli_connect("localhost", "my_user", "my_password", "world");
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
mysqli_query($link, "CREATE TABLE myCity LIKE City");
$query = "INSERT INTO myCity VALUES (NULL, 'Stuttgart', 'DEU', 'Stuttgart', 617000)";
mysqli_query($link, $query);
printf ("New Record has id %d.\n", mysqli_insert_id($link));
mysqli_query($link, "DROP TABLE myCity");
mysqli_close($link);
?>
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Результат выполнения данного примера:
 add a note
User Contributed Notes
mysqli_insert_id
Nick Baicoianu
04-May-2007 01:10
When running extended inserts on a table with an AUTO_INCREMENT field, the value of mysqli_insert_id() will equal the value of the *first* row inserted, not the last, as you might expect.
<?
//mytable has an auto_increment field
$db->query("INSERT INTO mytable (field1,field2,field3) VALUES ('val1','val2','val3'),
('val1','val2','val3'),
('val1','val2','val3')");
echo $db->insert_id; //will echo the id of the FIRST row inserted
?>
will at phpfever dot com
20-Apr-2006 06:40
I have received many statements that the insert_id property has a bug because it "works sometimes". Keep in mind that when using the OOP approach, the actual instantiation of the mysqli class will hold the insert_id.
The following code will return nothing.
<?php
$mysqli = new mysqli('host','user','pass','db');
if ($result = $mysqli->query("INSERT INTO t (field) VALUES ('value');")) {
echo 'The ID is: '.$result->insert_id;
}
?>
This is because the insert_id property doesn't belong to the result, but rather the actual mysqli class. This would work:
<?php
$mysqli = new mysqli('host','user','pass','db');
if ($result = $mysqli->query("INSERT INTO t (field) VALUES ('value');")) {
echo 'The ID is: '.$mysqli->insert_id;
}
?>
matix.bg a gmail
14-Mar-2006 02:56
Some people are wondering how to get the ids of the rows inserted with loop. Here is it:
<?php
for (;;;) {
$stmt->execute();
$ids[] = $mysqli->insert_id;
}
?>
alan at commondream dot net
03-Nov-2004 11:44
I was having problems with getting the inserted id, and did a bit of testing. It ended up that if you commit a transaction before getting the last inserted id, it returns 0 every time, but if you get the last inserted id before committing the transaction, you get the correct value.
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mysqli_init