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imagearc

(PHP 3, PHP 4, PHP 5)

imagearc -- Draws an arc

Описание

bool imagearc ( resource image, int cx, int cy, int width, int height, int start, int end, int color )

imagearc() draws an arc of circle centered at the given coordinates.

Список параметров

image

An image resource, returned by one of the image creation functions, such as imagecreatetruecolor().

cx

x-coordinate of the center

cy

y-coordinate of the center

width

The arc width

height

The arc height

start

The arc start angle, in degrees.

end

The arc end angle, in degrees. 0° is located at the three-o'clock position, and the arc is drawn clockwise.

color

A color identifier created with imagecolorallocate()

Возвращаемые значения

Возвращает TRUE в случае успешного завершения или FALSE в случае возникновения ошибки.

Примеры

Пример 1. Drawing a circle with imagearc()

<?php

// create a 200*200 image
$img = imagecreatetruecolor(200, 200);

// allocate some colors
$white = imagecolorallocate($img, 255, 255, 255);
$red   = imagecolorallocate($img, 255,   0,   0);
$green = imagecolorallocate($img,   0, 255,   0);
$blue  = imagecolorallocate($img,   0,   0, 255);

// draw the head
imagearc($img, 100, 100, 200, 2000, 360, $white);
// mouth
imagearc($img, 100, 100, 150, 150, 25, 155, $red);
// left and then the right eye
imagearc($img607550500, 360, $green);
imagearc($img, 1407550500, 360, $blue);

// output image in the browser
header("Content-type: image/png");
imagepng($img);

// free memory
imagedestroy($img);

?>

Результатом выполнения данного примера будет что-то подобное:



imagechar> <imageantialias
Last updated: Sat, 27 Jan 2007
 
add a note add a note User Contributed Notes
imagearc
mojiro at awmn dot net
13-Dec-2005 12:28
A previous for the Rotated (Filled)Ellipse note from(nojer2 at yahoo dot com, 02-Apr-2001 12:06) has a mistake, at the second arc. Replace them with the following listing.

if ($filled) {
    triangle($im, $cx, $cy, $cx+$px, $cy+$py, $cx+$x, $cy+$y, $colour);
    triangle($im, $cx, $cy, $cx-$px, $cy-$py, $cx-$x, $cy-$y, $colour);
} else {
    imageline($im, $cx+$px, $cy+$py, $cx+$x, $cy+$y, $colour);
    imageline($im, $cx-$px, $cy-$py, $cx-$x, $cy-$y, $colour);
}
ruturaj_v at yahoo dot com
17-May-2004 06:32
this is another piechart eg. very simple ...

<?php
global $deg;

function
get_polar($xrel, $yrel, $ang, $radius) {
   
$i = $ang;
   
$ang = ($ang * pi())/ 180;
   
   
$ix = abs($radius*cos($ang));
   
$iy = abs($radius*sin($ang));
   
    if (
$i>=0 && $i<=90) {
       
$ix = $xrel + $ix;
       
$iy = $yrel - $iy;
    }
    if (
$i>90 && $i<=180) {
       
$ix = $xrel - $ix;
       
$iy = $yrel - $iy;
    }
    if (
$i>180 && $i<=270) {
       
$ix = $xrel - $ix;
       
$iy = $yrel + $iy;
    }
    if (
$i>270 && $i<=360) {
       
$ix = $xrel + $ix;
       
$iy = $yrel + $iy;
    }

   
$ix = floor($ix);
   
$iy = floor($iy);
   
//echo ($ix . " $iy<br>");
   
$returnvals = array (
                       
'x1' => $xrel,
                       
'y1' => $yrel,
                       
'x2' => $ix,
                       
'y2' => $iy
                       
);
    return
$returnvals;
}

function
get_degtotal($degindex)
{
    global
$deg;
    if (
$degindex == 0 ) {
       return ( 
$deg[$degindex] );
    }
    else {       
        return (
$deg[$degindex] + get_degtotal($degindex-1) );
    }   
}

$im  = imagecreate (400, 400);
$w   = imagecolorallocate ($im, 255, 255, 255);
$black   = imagecolorallocate ($im, 0, 0, 0);
$red = imagecolorallocate ($im, 255, 0, 0);
$green = imagecolorallocate ($im, 0, 180, 0);

$randcolor[0] = imagecolorallocate($im, 243, 54, 163);
$randcolor[1] = imagecolorallocate($im, 179, 51, 247);
$randcolor[2] = imagecolorallocate($im, 103, 48, 250);
$randcolor[3] = imagecolorallocate($im, 53, 145, 244);
$randcolor[4] = imagecolorallocate($im, 54, 243, 243);
$randcolor[5] = imagecolorallocate($im, 107, 245, 180);
$randcolor[6] = imagecolorallocate($im, 203, 242, 111);
$randcolor[7] = imagecolorallocate($im, 248, 201, 105);

$data[0] = 30;
$data[1] = 20;
$data[2] = 15;
$data[3] = 10;
$data[4] = 8;
$data[5] = 7;
$data[6] = 5;
$data[7] = 5;

$datasum = array_sum($data);

$deg[0] = number_format((30 / $datasum * 360), 2, ".", "");
$deg[1] = number_format((20 / $datasum * 360), 2, ".", "");
$deg[2] = number_format((15 / $datasum * 360), 2, ".", "");
$deg[3] = number_format((10 / $datasum * 360), 2, ".", "");
$deg[4] = number_format((8 / $datasum * 360), 2, ".", "");
$deg[5] = number_format((7 / $datasum * 360), 2, ".", "");
$deg[6] = number_format((5 / $datasum * 360), 2, ".", "");
$deg[7] = number_format((5 / $datasum * 360), 2, ".", "");
echo (
'<pre>');

//print_r($deg);

$datadeg = array();
$datapol = array();
$degbetween = array();
$databetweenpol = array();

for (
$i=0; $i < count($deg) ; $i++) {
   
$datadeg[$i] = get_degtotal($i);
   
$datapol[$i] = get_polar(200, 200, $datadeg[$i], 100);
}

for (
$i=0; $i < count($datadeg) ; $i++) {
   
/*this is a trick where you take 2deg angle before
    and get the smaller radius so that you can have a pt to
    `imagefill` the chartboundary
    */
   
$degbetween[$i] = ($datadeg[$i]-2);
   
$databetweenpol[$i] = get_polar(200, 200, $degbetween[$i], 50);
}

print_r($datadeg);
print_r($degbetween);
print_r($databetweenpol);
//exit;

for ($i=0; $i<count($deg); $i++) {
   
imageline ($im, 200, 200, $datapol[$i]['x2'], $datapol[$i]['y2'], $black);
}
imagearc($im, 200, 200, 200, 200, 0, 360, $black);

for (
$i=0; $i<count($deg); $i++) {
   
imagefill ($im, $databetweenpol[$i]['x2'], $databetweenpol[$i]['y2'], $randcolor[$i]);

}

//header ("Content-type: image/png");
imagepng($im, 'piechart.png');
?>
<img src='piechart.png'>
jerryscript at aol dot com
26-Dec-2003 02:05
[note-Apache/1.3.29 (Win32) PHP/4.3.4]

The imagearc (and imageellipse) functions do not accept line thicknesses when drawn from 0 to 360 degrees.

Drawing from 0 to 359 and again from 359 to 360 does create an ellipse with the current line thickness.

Jerry
eamon at hostelworld dot com
17-Dec-2003 07:24
Right...
possibly the easiest way of drawing a filled circle:
Loop through the imagearc function incrementing the diameter by one pixel:
<?
 // --- code fragment --- //

for($i=1; $i<$Diameter; $i++){
  imagearc($Image, $CenterX, $CenterY, $i, $i, $Start, $End, $Color);
}

// --------------------- //

?>

This works great for circles with diameters up to about 60 or 70 pixels wide. After that, you start to get pixle gaps.
logang at deltatee dot com
04-Aug-2003 08:19
Heres a function to make a curve between two points... This will be a downward curve but it wouldn't be hard to make a similar function to make an upward curve. The first point has to be to the left of the second point ($x1 < $x2), and height is actually backwards. The larger height is the less of a crest the curve has. I imagine with a few modifications this functions could make upward curves as well.

function ImageCurveDown ($image, $x1, $y1, $x2, $y2, $height, $color) {
    $presicion = 1;

    for ($left = ($x1-$x2); $left < 0; $left++){
        if ($y1 < $y2) {
            $cy = $y2 + $height;
            $cx = $x1 - $left;
        } else {
            $cy = $y1 + $height;
            $cx = $x2 + $left;
        }
        $nx1 = abs($x1 - $cx);
        $ny1 = abs($y1 - $cy);
        $nx2 = abs($x2 - $cx);
        $ny2 = abs($y2 - $cy);

        if ($y1 < $y2) {
            if ($nx2 == 0 || $ny1 == 0) continue;
            $angle1 = atan($height/$nx2);
            $A1 = $nx2/cos ($angle1);
            $B1 = $ny2/sin ($angle1);
            $angle2 = pi()/2 +atan($left/$ny1);
            $A2 = $nx1/cos ($angle2);
            $B2 = $ny1/sin ($angle2);
        } else {
            if ($ny2 == 0 || $nx1 == 0) continue;
            $angle1 = atan($ny2/$nx2);
            $A1 = abs($nx2/cos ($angle1));
            $B1 = abs($ny2/sin ($angle1));
            $angle2 = atan($height/$nx1);
            $A2 = abs ($nx1/cos ($angle2));
            $B2 = abs($ny1/sin ($angle2));
        }

        if (abs($A1 - $A2) < $presicion && abs ($B1 - $B2) < $presicion) {
            ImageArc($image, $cx, $cy, $A1*2, $B1*2, 180+rad2deg($angle2), 360-rad2deg($angle1), $color);
        }
    }
}
23-Jan-2003 08:55
Please note that in order to draw a complete circle or ellipse (without using the imageellipse) you mustn't use 0
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